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Table 1 Orthophylogram distances

From: Mycobacterium tuberculosis and Clostridium difficille interactomes: demonstration of rapid development of computational system for bacterial interactome prediction

  CD Yeast Human
Mtb 1-(888 + 868)/(4020 + 4147) = 0.785 1-(735 + 523)/(6717 + 4020) = 0.883 1-(472 + 452)/(22500 + 4020) = 0.9652
CD   1-(374 + 603)/(6717 + 4147) = 0.91 1-(366 + 338)/(22500 + 4147) = 0.9735
Yeast    1-(2206 + 2139)/(22500 + 6717) = 0.8512
  1. Table shows phylogenetic distances between Mtb and CD, and also their distances from yeast and human, based on the number of shared orthologs. Mtb and CD are closer to each other than to yeast or human. The number of orthologs are obtained from KEGG-Orthology [31]distance (A, B) = 1 - (number of proteins in A that have orthologs in B + number of proteins in B that have orthologs in A)/(number of proteins in A + number of proteins in B)